g = 9.8 m/s2
g' = (9.83 - 0.0055) = 9.8245 m/s2
R = 6.37
R' = R + h = (6.37 + h)
A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055m/s2 less than that at sea level (gsealevel = 9.83 m/s2).
What is the observatory's altitude? Assume Rearth = 6.37
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