q1 = 5.4 μC(10-6C/1μC) = 5.4 × 10-6 C
q2 = 2.4 μC(10-6C/1μC) = 2.4 × 10-6 C
q3 = -3.0 μC(10-6C/1μC) = -3.0 × 10-6 C
d = 10.0cm(1m/100cm) = 0.1 m
let q2 and q3 be separated by x m
Then, q1 and q3 are separated by d - x = (0.1 - x)
Two charged balls, one with a charge of +5.0 μC and the other with a charge of +2.4 μC, are placed a distance d = 10.0 cm apart from each other and rigidly held in place. A third ball with a charge of -3.0 μC is dangled from a string between the two charged balls such that it remains in equilibrium. Calculate the distance the third charged ball is from to the +2.4 μC charge.
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