# Problem: A transverse harmonic wave travels on a rope according to the following expression:y(x,t) = 0.12sin(2.1x + 17.6t)a) At x = 3.8 m and t = 0.44 s, what is the velocity of the rope? (watch your sign)b) At x = 3.8 m and t = 0.44 s, what is the acceleration of the rope? (watch your sign)

###### FREE Expert Solution

(a)

Velocity:

$\overline{)\begin{array}{rcl}{\mathbf{v}}& {\mathbf{=}}& \frac{\mathbf{dy}}{\mathbf{dt}}\end{array}}$

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###### Problem Details

A transverse harmonic wave travels on a rope according to the following expression:

y(x,t) = 0.12sin(2.1x + 17.6t)

a) At x = 3.8 m and t = 0.44 s, what is the velocity of the rope? (watch your sign)

b) At x = 3.8 m and t = 0.44 s, what is the acceleration of the rope? (watch your sign)