Gravitational force:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{G}{\mathbf{M}}_{\mathbf{1}}{\mathbf{M}}_{\mathbf{2}}}{{\mathbf{R}}^{\mathbf{2}}}}$

Newton's second law:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{m}}{\mathbf{a}}}$

Solving for a:

$\begin{array}{rcl}\overline{){\mathbf{M}}_{\mathbf{e}}}\mathbf{a}& \mathbf{=}& \frac{{\mathbf{GM}}_{\mathbf{s}}\overline{){\mathbf{M}}_{\mathbf{e}}}}{{\mathbf{R}}^{\mathbf{2}}}\end{array}$

G = 6.67 × 10^{-11} N•m^{2}/kg^{2}

Mass of the sun, M_{s} = 1.99 × 10^{31} Kg

What is free-fall acceleration toward the sun at the distance of the earth's orbit? Express your answer to two significant figures and include the appropriate units.

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