Pressure in fluids:
Force and Pressure:
ρseawater = 1.03 × 103 Kg/m3
h = 25 m
g = 9.8 m/s2
diameter, d = 0.45 m
A = πr2 = π(d/2)2 = π(0.45/2)2 = 0.159 m2
A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of the sea water is 1.03 x 103 kg/m3. Calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.45m in diameter. The air pressure inside the submarine is 1.00 atm
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