Pressure in fluids:

$\overline{){\mathbf{P}}{\mathbf{=}}{\mathbf{h}}{\mathbf{\rho}}{\mathbf{g}}}$

Force and Pressure:

$\overline{){\mathbf{P}}{\mathbf{=}}\frac{\mathbf{F}}{\mathbf{A}}}$

ρ_{seawater} = 1.03 × 10^{3} Kg/m^{3}

h = 25 m

g = 9.8 m/s^{2}

diameter, d = 0.45 m

A = πr^{2} = π(d/2)^{2} = π(0.45/2)^{2} = 0.159 m^{2}

A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of the sea water is 1.03 x 10^{3} kg/m^{3}. Calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.45m in diameter. The air pressure inside the submarine is 1.00 atm

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