Using the kinematic equation

$\overline{){{\mathit{v}}}_{{\mathit{f}}}{\mathbf{=}}{{\mathit{v}}}_{{\mathbf{0}}}{\mathbf{+}}{\mathit{a}}{\mathit{t}}}$

Acceleration on the ski slope, a:

a = gsinθ = (9.81) sin (15°) = 2.54 m/s^{2}

You begin sliding down a 15° ski slope. Ignoring friction and air resistance, how fast will you be moving after 10s?

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