Centripetal acceleration:

$\overline{){{\mathbf{a}}}_{{\mathbf{c}}}{\mathbf{=}}\frac{{\mathbf{v}}^{\mathbf{2}}}{\mathbf{r}}}$

"Near the surface", the altitude can be taken to be zero. Thus, the radius of the orbit is the same as the radius of the moon.

v = C/T

C = 2πr

A satellite orbiting the moon very near the surface has a period of 110 min. What is the free-fall acceleration on the surface of the moon in SI units? [The mean radius of the moon is 1.74x10^{6} m.]

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