Problem: A car is parked at the top of a 52m -high hill. It slips out of gear and rolls down the hill.How fast will it be going at the bottom? (Ignore friction.)

FREE Expert Solution

Law of conservation of energy:

PE0+K.E0=PEf+K.Ef

mgh0+12mv02=mghf+12mvf2

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Problem Details

A car is parked at the top of a 52m -high hill. It slips out of gear and rolls down the hill.

How fast will it be going at the bottom? (Ignore friction.)