For a simple pendulum, the period is:

$\overline{){\mathbf{T}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi}}\sqrt{\frac{\mathbf{l}}{\mathbf{g}}}}$

$\begin{array}{rcl}{\mathbf{T}}_{\mathbf{e}}& \mathbf{=}& {\mathbf{2}}{\mathbf{\pi}}\sqrt{\frac{\mathbf{l}}{{\mathbf{g}}_{\mathbf{e}}}}\\ {\mathbf{T}}_{\mathbf{m}}& \mathbf{=}& {\mathbf{2}}{\mathbf{\pi}}\sqrt{\frac{\mathbf{l}}{{\mathbf{g}}_{\mathbf{m}}}}\end{array}$

A pendulum has a period of 0.69 s on Earth. What is its period on Mars, where the acceleration of gravity is about 0.37 that on Earth?

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