Problem: A transverse harmonic wave travels on a rope according to the following expression:y(x,t) = 0.12sin(2.1x + 17.6t)1) What is the amplitude of the wave?2) What is the frequency of oscillation of the wave?

FREE Expert Solution

The wave equation:

y(x,t)=Asin(kx+ωt)

1)

Amplitude = A

View Complete Written Solution
Problem Details

A transverse harmonic wave travels on a rope according to the following expression:

y(x,t) = 0.12sin(2.1x + 17.6t)

1) What is the amplitude of the wave?

2) What is the frequency of oscillation of the wave?