Basic trigonometry:

$\overline{){\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{\mathbf{}}{\mathbf{\theta}}{\mathbf{=}}\frac{\mathbf{o}\mathbf{p}\mathbf{p}\mathbf{o}\mathbf{s}\mathbf{i}\mathbf{t}\mathbf{e}}{\mathbf{h}\mathbf{y}\mathbf{p}\mathbf{o}\mathbf{t}\mathbf{e}\mathbf{n}\mathbf{u}\mathbf{s}\mathbf{e}}\phantom{\rule{0ex}{0ex}}{\mathbf{c}}{\mathbf{o}}{\mathbf{s}}{\mathbf{}}{\mathbf{\theta}}{\mathbf{=}}\frac{\mathbf{a}\mathbf{d}\mathbf{j}\mathbf{a}\mathbf{c}\mathbf{e}\mathbf{n}\mathbf{t}}{\mathbf{h}\mathbf{y}\mathbf{p}\mathbf{o}\mathbf{t}\mathbf{e}\mathbf{n}\mathbf{u}\mathbf{s}\mathbf{e}}}$

The weight of the ball, T_{A}, and T_{B} vectors make a right angle triangle such that:

T_{B} is the hypotenuse.

TA is the opposite

Weight is adjacent.

**(a)**

**cos θ = mg/T _{B}**

A large wrecking ball is held in place by two light steel cables.

a)

If the mass m of the wrecking ball is 4040 kg, what is the tension T_{B} in the cable that makes an angle of 40.0 with the vertical?

Take the free fall acceleration to be g = 9.80 m/^{s}.

b)

If the mass m of the wrecking ball is 4040 kg, what is the tension T_{A} in the horizontal cable?

Take the free fall acceleration to be g = 9.80 m/s^{2}.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the 2D Equilibrium concept. You can view video lessons to learn 2D Equilibrium. Or if you need more 2D Equilibrium practice, you can also practice 2D Equilibrium practice problems.

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