Problem: A large wrecking ball is held in place by two light steel cables.a)If the mass m of the wrecking ball is 4040 kg, what is the tension TB in the cable that makes an angle of 40.0 with the vertical?Take the free fall acceleration to be g = 9.80 m/s.b)If the mass m of the wrecking ball is 4040 kg, what is the tension TA in the horizontal cable?Take the free fall acceleration to be g = 9.80 m/s2.

FREE Expert Solution

Basic trigonometry:

sin θ=oppositehypotenusecos θ=adjacenthypotenuse

The weight of the ball, TA, and TB vectors make a right angle triangle such that:

TB is the hypotenuse.

TA is the opposite

Weight is adjacent.

(a)

cos θ = mg/TB

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Problem Details

A large wrecking ball is held in place by two light steel cables.

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a)

If the mass m of the wrecking ball is 4040 kg, what is the tension TB in the cable that makes an angle of 40.0^\circ with the vertical?

Take the free fall acceleration to be g = 9.80 m/s.


b)

If the mass m of the wrecking ball is 4040 kg, what is the tension TA in the horizontal cable?

Take the free fall acceleration to be g = 9.80 m/s2.