**(a)**

Bernoulli's equation:

$\overline{){{\mathbf{P}}}_{{\mathbf{1}}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{\rho}}{{{\mathbf{v}}}_{{}_{\mathbf{1}}}}^{{\mathbf{2}}}{\mathbf{+}}{\mathbf{\rho}}{\mathbf{g}}{{\mathbf{h}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{P}}}_{{\mathbf{2}}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{\rho}}{{{\mathbf{v}}}_{{\mathbf{2}}}}^{{\mathbf{2}}}{\mathbf{+}}{\mathbf{\rho}}{\mathbf{g}}{{\mathbf{h}}}_{{\mathbf{2}}}}$

Since v_{1} = v_{2} and given that the density of water is 1000 kg/m^{3}, we have:

A sump pump is draining a flooded basement at the rate of 0.600 L/s, with an output pressure of 3.00 x 10^{5}N/m^{2}. Neglect frictional losses in both parts of this problem.

(a) The water enters a hose with a 3.00 cm inside diameter and rises 2.50 m above the pump. What is its pressure at this point in N/m^{2}?

(b) The hose then loses 1.80 m in height from this point as it goes over the foundation wall, and widens to 4.00 cm diameter. What is the pressure now in N/m^{2}?

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