Newton's second law,
Block A applies/transmits a force FB to block B. Sum of forces on block B:
ΣFB = FB = mBaB
Block A experiences the applied force and reaction force from Block B. The reaction force from block B is equal to FB directed opposite to the applied force.
ΣFA = Fappied - FB = mAaA
Fapplied = FB + mAaA = mBaB + mAaA
aA = aB = a
3. Two blocks (A and B) are in contact on a horizontal frictionless surface. A 40 N constant horizontal force is applied to A. The mass of A is 3.0 kg and the mass of B is 12 kg. What is the magnitude of the force of A on B?
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