The time is unknown:
Solving for time:
Δy = v0,yt - (1/2)gt2
-235 = 0 - (1/2) × 9.8 × t2
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. The plane is traveling horizontally with a speed of 265 km/h (73.6 m/s).
(a) How far in advance of the recipients (horizontal distance) must the goods be dropped (Fig. 3-41 a)?
(b) Suppose, instead, that the plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (Fig. 3-41 b)? (Horizontal velocity is the same as in part (a)).
Magnitude: ___ m/s
(c) With what speed (magnitude of impact velocity) do the supplies land in the latter case?
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What scientific concept do you need to know in order to solve this problem?
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Based on our data, we think this problem is relevant for Professor Jerousek's class at UCF.