The time is unknown:
Solving for time:
Δy = v0,yt - (1/2)gt2
-235 = 0 - (1/2) × 9.8 × t2
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. The plane is traveling horizontally with a speed of 265 km/h (73.6 m/s).
(a) How far in advance of the recipients (horizontal distance) must the goods be dropped (Fig. 3-41 a)?
(b) Suppose, instead, that the plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (Fig. 3-41 b)? (Horizontal velocity is the same as in part (a)).
Magnitude: ___ m/s
(c) With what speed (magnitude of impact velocity) do the supplies land in the latter case?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Projectile Motion: Launch From Moving Vehicle concept. If you need more Projectile Motion: Launch From Moving Vehicle practice, you can also practice Projectile Motion: Launch From Moving Vehicle practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Dean's class at COLUMBIA.