🤓 Based on our data, we think this question is relevant for Professor Arakelyan's class at BC.

Impulse:

$\overline{){\mathbf{I}}{\mathbf{=}}{\mathbf{F}}{\mathbf{t}}}$

Change in momentum:

$\overline{){\mathbf{\u2206}}{\mathbf{P}}{\mathbf{=}}{{\mathbf{mv}}}_{{\mathbf{f}}}{\mathbf{-}}{{\mathbf{mv}}}_{{\mathbf{0}}}}$

Impulse is equal to force under the curve:

I = (1/2)bh + l•w + (1/2)bh = (1/2)(2 - 0)F_{max} + (4 - 2)F_{max} + (1/2)(6 - 2)F_{max} = 4F_{max} N.ms

I = 4F_{max} N.ms (10^{-3} s/ 1ms) = 0.004Fmax N•s

Change in momentum:

A 60g tennis ball with an initial speed of 32 m/s hits a wall and rebounds with the same speed. The figure shows the force of the wall on the ball during the collision. What is the value of F_{max}, the maximum value of the contact force during the collision? (2 sig figs)

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Impulse with Variable Forces concept. You can view video lessons to learn Impulse with Variable Forces. Or if you need more Impulse with Variable Forces practice, you can also practice Impulse with Variable Forces practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Arakelyan's class at BC.