Ohm's law:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{I}}{\mathbf{R}}}$

Series equivalent resistance:

$\overline{){{\mathbf{R}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}{{\mathbf{R}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{2}}}}$

R_{eq} = R_{1} + R_{2} = 10 + 5 = 15Ω

I_{CIRCUIT} = V/Req = 30/15 = 2 A

The potential difference across the 10 resistor is

A. 30 V.

B. 20 V.

C. 15 V.

D. 10 V.

E. 5 V.

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