Acceleration Due to Gravity Video Lessons

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Problem: Suppose the free-fall acceleration at some location on earth was exactly 9.8000 m/s2. What would it be at the top of a 1000m -tall tower at this location? (Ans. in 5 sig.figs)

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Acceleration due to gravity, g:

g=GMR2

At the height, h, the acceleration due to gravity will be:

gI=GM(R+h)2

Dividing gI by g:

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Problem Details

Suppose the free-fall acceleration at some location on earth was exactly 9.8000 m/s2. What would it be at the top of a 1000m -tall tower at this location? (Ans. in 5 sig.figs)

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