From the figure, each charge produces a vertical component. The vertical components are in the same axis as the weight. The weight is directed downward while the repulsive electric force is directed upward.
FE makes the hypotenuse. To solve for the opposite (vertical component of the electric force) we'll use the 'sin' trigonometric ratio. opp = hyp•sinθ
ΣF = 4FE•sinθ - mg = 0
Four equal positive point charges q are fixed to the corners of a horizontal square. A fifth positive point charge Q is on a free particle of mass m positioned directly above the center of the square, at a height equal to the length d of one side of the square. Refer to the figure.
Determine the magnitude of q in terms of defined quantities, the Coulomb constant, and g, if the system is in equilibrium.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Coulomb's Law (Electric Force) concept. You can view video lessons to learn Coulomb's Law (Electric Force). Or if you need more Coulomb's Law (Electric Force) practice, you can also practice Coulomb's Law (Electric Force) practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Lowhorn's class at CAL.