Equivalent capacitance in series:

$\overline{)\frac{\mathbf{1}}{{\mathbf{C}}_{\mathbf{e}\mathbf{q}}}{\mathbf{=}}\frac{\mathbf{1}}{{\mathbf{C}}_{\mathbf{1}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{C}}_{\mathbf{2}}}}$

Equivalent capacitance in parallel:

$\overline{){{\mathbf{C}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}{{\mathbf{C}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{C}}}_{{\mathbf{2}}}}$

**(1)**

From the equivalent capacitance equations, a series circuit decreases the overall capacitance.

The three configurations shown below are constructed using identical capacitors

1) Which of these configurations has the lowest overall capacitance?

a) A

b) B

c) C

d) All three configurations have the same capacitance

2) Briefly explain your reasoning

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