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# Problem: Find the angle between each of the following pairs of vectors A = Axi+Ayj and B = Bxi+ByjA) Ax1=-3.80, Ay1=4.60, Bx1=1.20, By1=-2.90B) Ax2=2.00, Ay2=6.00, Bx2=10.0, By2=5.20C) Ax3=-4.00, Ay3=2.00, Bx3=7.00, By3=14.00

###### FREE Expert Solution

Angle:

$\overline{){\mathbf{\theta }}{\mathbf{=}}{\mathbf{t}}{\mathbf{a}}{{\mathbf{n}}}^{\mathbf{-}\mathbf{1}}{\mathbf{\left(}}\frac{\mathbf{∆}\mathbf{y}}{\mathbf{∆}\mathbf{x}}{\mathbf{\right)}}}$

A)

The angle between A and negative x-axis:

α = tan-1(4.60/3.80) = 50.4° above the negative x-axis.

The angle measured anticlockwise from B, θ1 = 180 - 50.4 = 129.6°

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###### Problem Details

Find the angle between each of the following pairs of vectors A = Axi+Ayj and B = Bxi+Byj

A) Ax1=-3.80, Ay1=4.60, Bx1=1.20, By1=-2.90

B) Ax2=2.00, Ay2=6.00, Bx2=10.0, By2=5.20

C) Ax3=-4.00, Ay3=2.00, Bx3=7.00, By3=14.00

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