Force due to the charge at 3 cm is acting in the negative x-direction.
r = 8 - 3 = 5 cm.
F3 = (9 × 109) (q)(-2q)/(5 × 10-2)2 = - (9 × 109) (2)(0.85 × 10-6)2/(5 × 10-2)2 = - 5.20 N
As shown in the figure, there are 3 point charges along the x-axis located at 3, 8, and 11 cm.
What is the x-component of the force on the charge located at x = 8 cm given that q = 0.85 uC in N?
Fx = ?
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