Force:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{k}\mathbf{q}\mathbf{Q}}{{\mathbf{r}}^{\mathbf{2}}}}$

Force due to the charge at 3 cm is acting in the negative x-direction.

r = 8 - 3 = 5 cm.

F_{3} = (9 × 10^{9}) (q)(-2q)/(5 × 10^{-2})^{2} = - (9 × 10^{9}) (2)(0.85 × 10^{-6})^{2}/(5 × 10^{-2})^{2} = - 5.20 N

As shown in the figure, there are 3 point charges along the x-axis located at 3, 8, and 11 cm.

What is the x-component of the force on the charge located at x = 8 cm given that *q* = 0.85 uC in N?

*F _{x}* = ?