Problem: Rank these throws based on the maximum height reached by the ball.Rank from largest to smallest. To rank items as equivalent, overlap them.

FREE Expert Solution

Maximum height,

Hmax=v02 sin2θ2g

g = 9.8 m/s2

H1,max = (15 m/s)2(sin2 60) / (2)(9.8 m/s2) = 8.6 m

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Problem Details

Rank these throws based on the maximum height reached by the ball.

Rank from largest to smallest. To rank items as equivalent, overlap them.

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