(a) Energy stored, U,

$\overline{){\mathit{U}}{\mathbf{=}}\frac{\mathbf{C}{\mathbf{V}}^{\mathbf{2}}}{\mathbf{2}}}$

U = 44.8 J

C = 8.59 × 10^{-6} F

$\begin{array}{rcl}\mathbf{V}& \mathbf{=}& \sqrt{\frac{\mathbf{2}\mathbf{U}}{\mathbf{C}}}\\ & \mathbf{=}& \sqrt{\frac{\mathbf{2}\mathbf{\times}\mathbf{44}\mathbf{.}\mathbf{8}}{\mathbf{8}\mathbf{.}\mathbf{59}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{6}}}}\end{array}$

In open-heart surgery a small amount of energy will defibrillate the heart.

(a) What voltage is applied to the 8.59 μF capacitor of a heart defibrillator that stores 44.8 J of energy?

________KV

(b) Find the amount of stored charge.

________mC

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