Work done,

$\overline{){\mathbf{W}}{\mathbf{=}}{\mathbf{-}}{\mathbf{q}}{\mathbf{\xb7}}{\mathbf{\u2206}}{\mathbf{V}}}$

W_{ab} = 4.0 × 10^{-6} J

W_{c}_{b} = -6.5 × 10^{-6} J

It takes 4.0 μJ of work to move a 19 nC charge from point A to B. It takes -6.5 μJ of work to move the charge from C to B.

What is the potential difference V_{C}−V_{A}? Express your answer using two significant figures.