Part A

$\overline{){\mathbf{1}}{\mathbf{}}{\mathbf{m}}{\mathbf{i}}{\mathbf{l}}{\mathbf{e}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{1609}}{\mathbf{}}{\mathbf{m}}}$

Orbital speed, v,

$\overline{){\mathbf{v}}{\mathbf{=}}\sqrt{\frac{\mathbf{G}\mathbf{\xb7}\mathbf{M}}{\mathbf{R}}}}$

Height of orbit, H = 230 miles (1609 m / 1 mile) = 0.37 × 10^{6} m

Radius of the Earth, R = 6.37 × 10^{6 }m

Radius of the orbit, r = R + H = 6.37 × 10^{6} + 0.37 × 10^{6} = **6.74 × 10 ^{6} m**

Mass, m = 5.98 × 10^{24} kg

Gravitation constant, G = 6.673 × 10^{-11} N.m^{2} / kg^{2}

The International Space Station is in a 230-mile-high orbit.

Part A

What is the station's orbital speed? The radius of Earth is 6.37 × 10^{6 }m, its mass is 5.98 × 10^{24} kg.

Part B

What is the station's orbital period?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Satellite Motion: Speed & Period concept. You can view video lessons to learn Satellite Motion: Speed & Period. Or if you need more Satellite Motion: Speed & Period practice, you can also practice Satellite Motion: Speed & Period practice problems.

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