Problem: If the top circuit has an oscillation frequency of 1000 Hz, the frequency of the bottom circuit is?

Frequency of LC circuit:

$f = \frac{1}{2 π \sqrt{L C}}$

For the first circuit, the frequency is expressed as:

$\begin{array}{rcl} f & = & \frac{1}{2 π} \frac{1}{\sqrt{L C}} \\ \frac{1}{\sqrt{L C}} & = & 2 π f \\ = & 2 π (1000) \end{array}$

For the second circuit:

Equivalent capacitance for the second circuit:

$\begin{array}{rcl} \frac{1}{C_{e q}} & = & \frac{1}{C} + \frac{1}{C} \\ \frac{1}{C_{e q}} & = & \frac{2}{C} \end{array}$

If the top circuit has an oscillation frequency of 1000 Hz, the frequency of the bottom circuit is?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the LC Circuits concept. You can view video lessons to learn LC Circuits. Or if you need more LC Circuits practice, you can also practice LC Circuits practice problems.