Problem: A parallel-plate capacitor is formed from two 9.1 cm-diameter electrodes spaced 1.1 mm apart. The electric field strength inside the capacitor is 6.0×106 N/C. What is the charge (in nC) on each electrode?

FREE Expert Solution

Charge:

Q=EAε0

A = πr2 = (π)(d/2)2 = (π)[(9.1 × 10-2)/2]2 = 6.5 × 10-3  m2 

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Problem Details

A parallel-plate capacitor is formed from two 9.1 cm-diameter electrodes spaced 1.1 mm apart. The electric field strength inside the capacitor is 6.0×106 N/C. What is the charge (in nC) on each electrode?