$\overline{){\mathbf{1}}{\mathbf{}}{\mathit{P}}{\mathit{a}}{\mathbf{=}}{\mathbf{1}}{\mathbf{}}{\mathit{N}}{\mathbf{/}}{{\mathit{m}}}^{{\mathbf{2}}}}$

$\overline{){{\mathbf{P}}}_{\mathbf{g}\mathbf{a}\mathbf{s}}{\mathbf{=}}{{\mathbf{P}}}_{\mathbf{a}\mathbf{t}\mathbf{m}\mathbf{o}\mathbf{s}}{\mathbf{+}}{\mathbf{(}}{{\mathbf{h}}}_{{\mathbf{2}}}{\mathbf{-}}{{\mathbf{h}}}_{{\mathbf{1}}}{\mathbf{)}}{\mathbf{\rho}}{\mathbf{g}}}$

h_{1} = 13.5 cm (1 m / 100 cm) = 0.135 m

h_{2} = 6.00 cm (1 m / 100 cm) = 0.06 m

ρ = 1.36×10^{4} kg/m3

g = 9.8 m/s^{2}

Assume P_{atmos}=1.00atm. What is the gas pressure in the manometer P_{gas}? Express your answer in pascals to three significant figures.

h_{1} = 13.5 cm

h_{2} = 6.00 cm

Density of mercury = 1.36×10^{4} kg/m^{3}

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Pressure Gauge: Manometer concept. You can view video lessons to learn Pressure Gauge: Manometer. Or if you need more Pressure Gauge: Manometer practice, you can also practice Pressure Gauge: Manometer practice problems.

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