Work done

$\overline{)\begin{array}{rcl}\mathbf{W}& \mathbf{=}& \mathbf{q}\mathbf{\xb7}\mathbf{\u2206}\mathbf{V}\end{array}}$

Kinetic energy,

$\overline{)\begin{array}{rcl}\mathbf{KE}& \mathbf{=}& \frac{\mathbf{1}}{\mathbf{2}}{\mathbf{mv}}^{\mathbf{2}}\end{array}}$

ΔV = -3.45x10^{-3} V

q_{a} = 3.20x10^{ -19} C

m_{a} 6.68x10^{-27 }kg

**Part a)**

Change in kinetic energy is equal to work done.

An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of -3.45×10^{-3} V.

The charge and the mass of an alpha particle are q_{α} = 3.20x10^{ -19} C and m_{α} 6.68x10^{-27 }kg, respectively.

What is the value of the change in potential energy, Δ*U*=*U*_{f}−*U*_{i}, of the alpha particle? Express your answer in joules using three significant figures.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Electric Potential Energy concept. You can view video lessons to learn Electric Potential Energy. Or if you need more Electric Potential Energy practice, you can also practice Electric Potential Energy practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Ene's class at UH.