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Problem: An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of -3.45×10-3 V.The charge and the mass of an alpha particle are qα = 3.20x10 -19 C and mα 6.68x10-27 kg, respectively.What is the value of the change in potential energy, ΔU=Uf−Ui, of the alpha particle? Express your answer in joules using three significant figures.

FREE Expert Solution

Work done

W=q·V

Kinetic energy,

KE=12mv2

ΔV = -3.45x10-3 V

qa = 3.20x10 -19 C

ma 6.68x10-27 kg

Part a)

Change in kinetic energy is equal to work done. 

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Problem Details

An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of -3.45×10-3 V.

The charge and the mass of an alpha particle are qα = 3.20x10 -19 C and mα 6.68x10-27 kg, respectively.

What is the value of the change in potential energy, ΔU=UfUi, of the alpha particle? Express your answer in joules using three significant figures.

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