For a parallel-plate capacitor, capacitance is:

$\overline{){\mathbf{C}}{\mathbf{=}}\frac{{\mathbf{\epsilon}}_{\mathbf{0}}\mathbf{A}}{\mathbf{d}}}$

Therefore, capacitance is proportional to the area of the plates, A.

Capacitance is inversely proportional to the separation between plates, d.

Therefore:

Which of the following will increase the capacitance of a parallel-plate capacitor?

Check all that apply.

a) Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor.

b) Decreasing the area of the plates will increase the capacitance of a parallel-plate capacitor.

c) Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.

d) Increasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Parallel Plate Capacitors concept. You can view video lessons to learn Parallel Plate Capacitors. Or if you need more Parallel Plate Capacitors practice, you can also practice Parallel Plate Capacitors practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Kulyk's class at UCF.