Energy of Circular Orbits Video Lessons

Concept

# Problem: The International Space Station makes 15.65 revolutions per day in its orbit around the earth. Assuming a circular orbit, how high is this satellite above the surface of the earth?

###### FREE Expert Solution

$\overline{)\begin{array}{rcl}{\mathbf{T}}^{\mathbf{2}}& {\mathbf{=}}& \frac{\mathbf{4}{\mathbf{\pi }}^{\mathbf{2}}{\mathbf{r}}^{\mathbf{3}}}{\mathbf{G}\mathbf{M}}\end{array}}$

Periodic time, T = 1 day / 15.65 (24 hours / 1 day)(3600 s/ 1 hour) = 5521 s

G = 6.67 × 10-11 N•m2 / kg2

Mass of the earth, M = 5.98 × 1024 kg

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###### Problem Details

The International Space Station makes 15.65 revolutions per day in its orbit around the earth. Assuming a circular orbit, how high is this satellite above the surface of the earth?