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Problem: Three point charges are arranged along the x-axis. Charge q1 = 3 mc is at the origin and charge q2 = -5 mc is at x = 0.2 m. Charge q3 = -8.00 mc.Where is q3 located if the net force on q1 is 7.00 N in the -x-direction?

FREE Expert Solution

Force,

F=kq1q2r2

q1 =3 mC = 3 × 10-6 C

q2 = -5 mC = -5 × 10-6 C

q3 = -8.00 mC = -8 × 10-6 C

x12 = 0.2m

q1 is attracted by both q2 and q3. Fnet is directed to the left (negative) while F12 is directed to the right (positive).

F1, net=F12+F13F13=F1, net-F12=-7.00-kq1q2r122=-7.00-(9.0×109)(3.0×10-6)(5.0×10-6)0.22=-7.00-3.375=-10.37

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Problem Details

Three point charges are arranged along the x-axis. Charge q1 = 3 mc is at the origin and charge q2 = -5 mc is at x = 0.2 m. Charge q3 = -8.00 mc.

Where is q3 located if the net force on q1 is 7.00 N in the -x-direction?

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