q1 =3 mC = 3 × 10-6 C
q2 = -5 mC = -5 × 10-6 C
q3 = -8.00 mC = -8 × 10-6 C
x12 = 0.2m
q1 is attracted by both q2 and q3. Fnet is directed to the left (negative) while F12 is directed to the right (positive).
Three point charges are arranged along the x-axis. Charge q1 = 3 mc is at the origin and charge q2 = -5 mc is at x = 0.2 m. Charge q3 = -8.00 mc.
Where is q3 located if the net force on q1 is 7.00 N in the -x-direction?
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