w = mg = 2.0 N
θ = 30°
Displacement along incline = 1.8 m
Work done = opposite of change gravitational potential energy (U = mgh)
A box of weight w = 2.0N accelerates down a rough plane that is inclined at an angle 30° above the horizontal. The normal force acting on the box has a magnitude n = 1.7 N, the coefficient of kinetic friction between the box and the plane is μk=0.30, and the displacement of the box is 1.8 m down the inclined plane.
What is the work Ww done on the box by the weight of the box?
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