VA = (9.0 × 109)[(- 15.0 × 10-9)/(20.0 × 10-2)] = - 675 V
VB = (9.0 × 109)[(- 15.0 × 10-9)/(40.0 × 10-2)] = - 338 V
Suppose you have a fixed charge of -15.0 nC at point X. Points A and B are at distances of 20.0 cm and 40.0 cm from X as shown.
Calculate the following:
a) the potential at points A and B
b) the potential difference between A and B
c) the potential energy of a proton at A and B
d) the speed at point B of a proton that was moving to the right at point A with a speed of 4.0 × 105 m/s
e) the speed at point A of a proton that was moving to the left at point B with a speed of 1.0 × 105 m/s.
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