Problem: A thin 3.00 kg box rests on a 6.50 kg board that hangs over the end of a table, as shown in the figureHow far can the center of the box be from the end of the table before the board begins to tilt?

FREE Expert Solution

For seesaws, downward moments are the same as upward moments:

m1r1=m2r2

We'll take the moments about the edge of the table. 

m1 = [(30.0)/(30.0 + 20.0)](6.50) = 3.9kg

This acts at the center of 30.0cm on the left.

Thus, m1r1 = (3.9)(0.15) = 0.59 kg•m

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Problem Details

A thin 3.00 kg box rests on a 6.50 kg board that hangs over the end of a table, as shown in the figure

How far can the center of the box be from the end of the table before the board begins to tilt?

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Our tutors have indicated that to solve this problem you will need to apply the Equilibrium with Multiple Objects concept. You can view video lessons to learn Equilibrium with Multiple Objects. Or if you need more Equilibrium with Multiple Objects practice, you can also practice Equilibrium with Multiple Objects practice problems.