$\overline{){\mathbf{v}}{\mathbf{=}}\frac{\mathbf{\u2206}\mathbf{x}}{\mathbf{t}}}$

Linear momentum, P ,

$\overline{){\mathbf{P}}{\mathbf{=}}{\mathbf{m}}{\mathbf{v}}}$

Angular momentum, L,

$\overline{){\mathbf{L}}{\mathbf{=}}{\mathbf{r}}{\mathbf{P}}}$

Periodic time, T = 27.3 days = 27.3 day (24 hr/ 1 day)(3600 s / 1 hr) = 2,358,720 s

r = 3.8×10^{8}m

The moon's mass is 7.4×10^{22}kg and it orbits 3.8×10^{8}m from the earth with a period of 27.3 days.

What is the angular momentum of the moon around the earth?

Express your answer using two significant figures.

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