Problem: A 1.50 mm-diameter glass bead is positively charged. The potential difference between a point 1.50 mm from the bead and a point 3.60 mm from the bead is 460V.Note: The given distances are measured from the surface of the bead.What is the charge on the bead?

FREE Expert Solution

Potential difference:

V=q4πε0r

Radius, r  = 1.50/2 = 0.75 × 10- 3 m

The potential difference between the two points:

V1-V2=q4πε0r1-q4πε0r2=q4πε0(1r1-1r2)

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Problem Details

A 1.50 mm-diameter glass bead is positively charged. The potential difference between a point 1.50 mm from the bead and a point 3.60 mm from the bead is 460V.

Note: The given distances are measured from the surface of the bead.

What is the charge on the bead?

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