Coulomb's Law (Electric Force) Video Lessons

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Problem: The force of attraction between a -40.0 μC and + 108 μC charge is 4.00 N. What is the separation between these two charges?A) 1.13 m B) 2.10 m C) 3.12 m D) 2.49 m E) 3.67 m

FREE Expert Solution

 From Coulomb's law:

F=kq1q2r2

  • F = 4.00 N (Force of attraction)
  • k = 8.99 × 109 Nm2/C2 (Coulomb's Constant)
  • q1 = - 40.0 × 10-6 C
  • q2 = + 108 × 10-6 C
  • r = ? (separation between the charges)
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Problem Details

The force of attraction between a -40.0 μC and + 108 μC charge is 4.00 N. What is the separation between these two charges?

A) 1.13 m 

B) 2.10 m 

C) 3.12 m 

D) 2.49 m 

E) 3.67 m

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