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Problem: Two point charges are placed on the x-axis. The first charge, q1 = 8.00 nC, is placed a distance 16.0 m from the origin along the positive x-axis; the second charge, q2 = 6.00 nC, is placed a distance 9.00 m from the origin along the negative x-axis.(a) Calculate the electric field at point A, located at coordinates (0 m, 12.0 m).(b) Give the x and y components of the electric field as an ordered pair.Express your answer in newtons per coulomb to three significant figures.EAx, EAy =

FREE Expert Solution

Electric field,

E=kqr2

Vector magnitude:

|r|=rx2+ry2

Direction for angles measured from the x-axis:

tan θ=ryrx

Resolving vector components:

Ex=|E| cos θEy=|E| sin θ

a)

r1 = (-16.0 i + 12 j ) m (the vector moves in the negative x-direction)

|r1|=r1x2+r1y2=(-16.0)2+(12.0)2

|r1| = 20 m

θ1 = tan-1 (r1y/r1x) = tan-1 (12/-16) = -36.9° (negative x-component shows that the angle is above the the negative x-axis).

From the positive x-axis:

θ1 = 180 - 36.9 = 143.1

r2 = (9 i + 12 j) m (the vector moves in the positive x-direction)

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Problem Details

Two point charges are placed on the x-axis. The first charge, q1 = 8.00 nC, is placed a distance 16.0 m from the origin along the positive x-axis; the second charge, q2 = 6.00 nC, is placed a distance 9.00 m from the origin along the negative x-axis.

(a) Calculate the electric field at point A, located at coordinates (0 m, 12.0 m).

(b) Give the x and y components of the electric field as an ordered pair.

Express your answer in newtons per coulomb to three significant figures.

EAx, EAy =

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