The two objects in the figure below are balanced o...

Question

The two objects in the figure below are balanced on the pivot, with m = 1.7 kg. What is distance d?

Patrick Ford · Accepted Answer

A Moment (torque) is the product of Force and Distance.τ=F·r sin θ F=mgLet clockwise torque be positive and counter-clockwise torque be negative.The system is in equilibrium. Therefore, the sum torque should be zero. Στ=0Στcw-Στccw=0[readmore]Let us locate our reference rotational point on the left side of the 2.0 m length. We'll have the following torques;The torque due to the weight of the masses, m = 1.7 kg and m = 4.0 kg, acting clockwise. The torque due to the reaction (P) from the pivot acting counter-clockwise.Forces causing the torquesF1.7 = 1.7 kg × 9.8 m/s2 = 16.66 NF4.0 = 4.0 kg × 9.8 m/s2 = 39.2 NFrom Newton's second law, Σ(upwards forces+downward forces) = ma = 0. Let, upward be positive and downward negative. F1.7 + F4.0 - P = 016.66 N + 39.2 N - P = 0P = 55.86 NDistance (r) of the Forces from the left end;r1.7 = 2.0 m / 2 = 1.0 m (weight acts at the midpoint)r4.0 = 1m + (1.0 m / 2) = 1.5 md = ?All the forces and distances are perpendicular. That is, θ = 90°.We'll solve for d from using the torque expression.Στcw-Στccw=0τ1.7+τ4.0-τp=0(16.66)(1.0)sin 90+(39.2)(1.5)sin 90-(55.86)(d)sin 90=055.86d=16.66+58.8d=1.35d = 1.35 m

Problem: The two objects in the figure below are balanced on the pivot, with m = 1.7 kg. What is distance d?

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Problem Details

Problem: The two objects in the figure below are balanced on the pivot, with m = 1.7 kg. What is distance d?

FREE Expert Solution

Problem Details

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