Using the kinematic equation:

$\overline{){\mathbf{\u2206}}{\mathbf{y}}{\mathbf{=}}{{\mathbf{v}}}_{{\mathbf{0}}}{\mathbf{t}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{g}}{{\mathbf{t}}}^{{\mathbf{2}}}}$

To get time, t:

v_{0} = 0 m/s and Δy = 2.3 m.

A pipe discharges storm water into a creek. Water flows horizontally out of the pipe at 1.8 m/s, and the end of the pipe is 2.3 m above the creek.

How far out from the end of the pipe is the point where the stream of water meets the creek?

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