Electric field due to point charge:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{k}\mathbf{q}}{{\mathbf{r}}^{\mathbf{2}}}}$

Vector magnitude and direction:

$\overline{)\mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathbf{r}}\mathbf{\right|}{\mathbf{=}}\sqrt{{{\mathbf{r}}_{\mathbf{x}}}^{\mathbf{2}}\mathbf{+}{{\mathbf{r}}_{\mathbf{y}}}^{\mathbf{2}}}}$

$\overline{){\mathbf{tan}}{\mathbf{\theta}}{\mathbf{=}}\frac{{\mathit{r}}_{\mathbf{y}}}{{\mathit{r}}_{\mathbf{x}}}}$

A point charge q_{1} = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q_{2} = +6.00 nC is at the point x = 0.600 meters, y = 0.

A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.

B) What is the direction, relative to the negative *x-axis*, of the net electric field at the origin due to these two point charges?