Torque given by

**τ = Fr sinθ**

θ = 90° → sinθ = 1

F = mg

r = distance between fulcrum and CoM

The center of mass of a 0.40 kg (non-uniform) meter stick is located at its 47-cm mark. What is the magnitude of the torque (in N**·**m) due to gravity if it is supported at the 30-cm mark? (Use g = 9.79 m/s^{2}).