Torque Due to Weight Video Lessons

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Problem: The center of mass of a 0.40 kg (non-uniform) meter stick is located at its 47-cm mark. What is the magnitude of the torque (in N·m) due to gravity if it is supported at the 30-cm mark? (Use g = 9.79 m/s2).

FREE Expert Solution

Torque given by

τ = Fr sinθ

θ = 90° → sinθ = 1

F = mg

r = distance between fulcrum and CoM

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Problem Details

The center of mass of a 0.40 kg (non-uniform) meter stick is located at its 47-cm mark. What is the magnitude of the torque (in N·m) due to gravity if it is supported at the 30-cm mark? (Use g = 9.79 m/s2).

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