Vertical Forces and Acceleration Video Lessons

Concept

# Problem: A 6 kg bucket of water is being pulled straight up by a string at a constant speed.(a) What is the tension on the string?(b) At a certain point, the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now?(c) Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude 3 m/s2. What is the tension in the rope?

###### FREE Expert Solution

Newton's Second Law Equation:

$\overline{){\mathbf{\Sigma F}}{\mathbf{=}}{\mathbf{ma}}}$

(a) At a constant velocity, the acceleration is zero:

T - mg = 0

T = mg

• m = 6kg
• g = 9.8 m/s2
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###### Problem Details

A 6 kg bucket of water is being pulled straight up by a string at a constant speed.
(a) What is the tension on the string?
(b) At a certain point, the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now?
(c) Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude 3 m/s2. What is the tension in the rope?