Problem:  6 kg bucket of water is being pulled straight up by a string at a constant speed. I determined that the tension on the string wasF = maF = (6kg * 9.8 m/s2)F = 58.8 N.(a) At a certain point, the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now?(b) Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude 3 m/s2. What is the tension in the rope?

FREE Expert Solution

Newton's Second Law Equation:

ΣF=ma

(a) Forces acting on the bucket:

T-mg=maT=mg+ma=m(g+a)

  • m = 6kg
  • g = 9.8 m/s2
  • a = 3 m/s2
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Problem Details

 6 kg bucket of water is being pulled straight up by a string at a constant speed. I determined that the tension on the string was

F = ma
F = (6kg * 9.8 m/s2)
F = 58.8 N.

(a) At a certain point, the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now?

(b) Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude 3 m/s2. What is the tension in the rope?