$\overline{){\mathbf{v}}{\mathbf{=}}{\mathbf{f}}{\mathbf{\lambda}}}$

The resonant frequency for a pipe with one open end and one closed end is given by:

$\overline{){\mathbf{f}}{\mathbf{=}}\frac{\mathbf{n}\mathbf{v}}{\mathbf{4}\mathbf{L}}}$

Since L_{1} is greater than L_{2} and that they represent neighbouring resonances, then:

Using the two measured pipe lengths (L_{1} = 66cm and L_{2} = 40 cm), work out the wavelength of the sound wave. Use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L_{1} and L_{2} represent neighboring resonances (i.e, n and n+2). The pipes are open on one end and closed on the other. Frequency of tuning fork is 384 Hz.