Problem: Using the two measured pipe lengths (L1 = 66cm and L2 = 40 cm), work out the wavelength of the sound wave. Use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L1 and L2 represent neighboring resonances (i.e, n and n+2). The pipes are open on one end and closed on the other. Frequency of tuning fork is 384 Hz.

FREE Expert Solution

v=fλ

The resonant frequency for a pipe with one open end and one closed end is given by:

f=nv4L

Since L1 is greater than L2 and that they represent neighbouring resonances, then:

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Problem Details

Using the two measured pipe lengths (L1 = 66cm and L2 = 40 cm), work out the wavelength of the sound wave. Use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L1 and L2 represent neighboring resonances (i.e, n and n+2). The pipes are open on one end and closed on the other. Frequency of tuning fork is 384 Hz.