Force on Moving Charges & Right Hand Rule Video Lessons

Video Thumbnail

Concept

Problem: An electron at point A in the figure has a speed of 1.49 × 106 m/s.(a) Find the direction of the magnetic field that will cause the electron to follow the semicircular path from A to B.(b) Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.(c) Find the time required for the electron to move from A to B.(d) Find the direction of the magnetic field, that would be needed if the particle were a proton instead of an electron?(e) Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron?

FREE Expert Solution

(a) Lorentz force:

FB=qvBsinθ

92% (129 ratings)
View Complete Written Solution
Problem Details

An electron at point A in the figure has a speed of 1.49 × 106 m/s.

(a) Find the direction of the magnetic field that will cause the electron to follow the semicircular path from A to B.

(b) Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.

(c) Find the time required for the electron to move from A to B.

(d) Find the direction of the magnetic field, that would be needed if the particle were a proton instead of an electron?

(e) Find the magnitude of the magnetic field, that would be needed if the particle were a proton instead of an electron?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Force on Moving Charges & Right Hand Rule concept. You can view video lessons to learn Force on Moving Charges & Right Hand Rule. Or if you need more Force on Moving Charges & Right Hand Rule practice, you can also practice Force on Moving Charges & Right Hand Rule practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Sinkovic's class at UCONN.