Problem: A. What is the magnitude of the electric force on charge A in the figure?F=______NB. What is the direction of the electric force on charge A in the figure? Choose the best answer.(a) to the left(b) to the right(c) the force is zero

FREE Expert Solution

A. Electric force at point A is due to the charges at point B and C.

We apply Coulomb's law between points A and B and again between points A and C.

$F = \frac{{kq}_{1} q_{2}}{r^{2}}$

Between A and B

$\begin{array}{rcl} F_{A B} & = & \frac{{kq}_{A} q_{B}}{{r_{AB}}^{2}} \end{array}$

k = 8.99 × 10⁹Nm²/C² (Coulomb's constant)
q_A = 1.0 × 10^-⁹ C
q_B = - 1.0 × 10^-⁹ C
r_AB = 1 × 10^-3 m

Substituting:

$\begin{array}{rcl} F_{AB} & = & \frac{(8.99 \times 10^{9} {Nm}^{2} / C^{2}) (1.0 \times 10^{- 9} C) (- 1.0 \times 10^{- 9} C)}{{(1.0 \times 10^{- 3} m)}^{2}} \\ = & \frac{(8.99 \times 10^{9} N m^{2} / C^{2}) [(1.0 \times 10^{- 9}) (- 1.0 \times 10^{- 9})] C^{2}}{1.0 \times 10^{- 6} m^{2}} \end{array}$

F_AB = - 8.99 × 10^-3N

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Problem Details

A. What is the magnitude of the electric force on charge A in the figure?

F=______N

B. What is the direction of the electric force on charge A in the figure? Choose the best answer.

(a) to the left

(b) to the right

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Problem: A. What is the magnitude of the electric force on charge A in the figure?F=______NB. What is the direction of the electric force on charge A in the figure? Choose the best answer.(a) to the left(b) to the right(c) the force is zero

FREE Expert Solution

Problem Details

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