The condition for constructive interference is given as:

$\overline{)\begin{array}{rcl}\mathbf{d}\mathbf{}\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{}\mathbf{\theta}& {\mathbf{=}}& \mathbf{m}\mathbf{\lambda}\end{array}}$

Therefore, the angle θ becomes:

$\overline{){\mathbf{\theta}}{\mathbf{=}}{\mathbf{s}}{\mathbf{i}}{{\mathbf{n}}}^{\mathbf{-}\mathbf{1}}{\mathbf{\left(}}\frac{\mathbf{m}\mathbf{\lambda}}{\mathbf{d}}{\mathbf{\right)}}}$

The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating having 750 lines/mm, over what range of angles does the visible m = 1 spectrum extend?

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