In this problem, we have both cross and dot products of vectors.
Newton's second law:
m = 2.00kg
F = = (6.00 N) (8.00 N) (4.00 N)
We are dividing a vector by a scalar.
At the instant the displacement of a 2.00 kg object relative to the origin is = (2.00 m) (4.00 m) (3.00 m) , its velocity is = (6.00 m/s) (3.00 m/s) (3.00 m/s) and it is subject to a force = (6.00 N) (8.00 N) (4.00 N) . Find
(a) the acceleration of the object,
(b) the angular momentum of the object about the origin,
(c) the torque about the origin acting on the object, and
(d) the angle between the velocity of the object and the force acting on the object.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Angular Momentum & Newton's Second Law concept. You can view video lessons to learn Angular Momentum & Newton's Second Law. Or if you need more Angular Momentum & Newton's Second Law practice, you can also practice Angular Momentum & Newton's Second Law practice problems.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Fundamentals of Physics - Halliday Calc 10th Edition. You can also practice Fundamentals of Physics - Halliday Calc 10th Edition practice problems.