🤓 Based on our data, we think this question is relevant for Professor Perez's class at MEMPHIS.
This problem asks us to calculate the vertical and horizontal distance the dart travels, given the initial velocity and time of flight.
For projectile motion problems in general, we'll follow these steps to solve:
The four UAM (kinematics) equations are:
We define our coordinate system so that the +y-axis is pointing upwards and the +x-direction is horizontal along the launch direction. That means ay = −g, and ax = 0 (because after a projectile is launched, the only acceleration is due to gravity.)
For a horizontally launched projectile, we also know that v0y = 0.
A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull’s-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later.
(a)What is the distance PQ?
(b) How far away from the dart board is the dart released?